Răspuns:
Explicație:
1. Z=19----->19e,19p
2kmoli K=2000moli K
1mol K------------19. 6,023.10²³ e
2000moli K------------x
x=2000 . 19 . 6,023.10²³=228874 .10²³ e
2. Z=11------>11p,11e
o,46kg=460g Na
n=460g : 23g/moli=20 moli Na
1mol Na---------11 . 6,023.10²³p
20moli Na----------x
x=20 . 11. 6,023.10²³ p =1325,06 .10²³ p
3.
4moli Li
Li are Z=3 ------> 3p , 4n, 3e
A=7 nucleonii sunt : p si n
1mol Li----------3.6,023.10²³ p--------------4. 6,023.10²³ n
4moli---------------x----------------------------------------y
x=4 . 3 . 6,023.10²³p=72,276 .10²³p
y=4 . 4 .6,023.10²³ n=96,368 .10²³ n
aduna-le !
