Răspuns:
dac e in Z3 , toate au caciulite
Explicație pas cu pas:
2+(m-1)X²+(2m²-3m+1)X³
(2m²-3m+1)=0
m1,2=(3+-√1)/4...m1=1/3...m2=1
2(m-1)(m-1/3)X³+(m-1)X²+2
m∈R\{1/3;1}....grad3
m=1/3......grad2..(m-1)X²+2
m=1....grad 0...ramane 2, un nr
b)f€Z3; f=1+mX+(m²-m)X²; la
m(m-1)X²+mx+1
m=1^...grad1 ramane mx+1
m=0^...grad 0 ramane 1, orice nr se considera pol de grad 0
m=2^... grad2...2X²+2X+1