f(x) = x + 1
Calculam:
f(2x+1) = (2x+1) + 1 = 2x + 2
f(3x-1) = (3x-1) + 1 = 3x
f(x+2) = (x+2) + 1 = x + 3
f(3) = 3 + 1 = 4
Ecuația de rezolvat :
f(2x+1) + f(3x-1) = f(x) + f(x+2) + f(3)
2x + 2 + 3x = x + 1 + x + 3 + 4
5x + 2 = 2x + 8
5x - 2x = 8 - 2
3x = 6
x = 6 : 3
x = 2
R: x = 2