[tex]\left(\frac{1}{2}\right)^3+\frac{\frac{\left(\frac{2}{3}-\frac{5}{12}\right)^2+1}{6-\left(\frac{93}{90}-\frac{39}{45}\right)}}{\frac{3}{2}\times \:6}=\frac{61}{420}[/tex]
[tex]\left(\frac{1}{2}\right)^3=\frac{1}{2^3}[/tex]
[tex]=\frac{1}{2^3}+\frac{17}{840}[/tex]
[tex]=\frac{1}{8}+\frac{17}{840}[/tex]
[tex]=\frac{105+17}{840}[/tex]
[tex]=\frac{122}{840}[/tex]
[tex]=\frac{61}{420}[/tex]
Sper că te-am ajutat!
Succes l-a școală!
