Răspuns :
x+6√3+2x√3+3=0
x(1+2√3)=-(6√3+3)
x=-(6√3+3)/(1+2√3) rationalizam
x=-(6√3+3)(1-2√3)/(1+2√3)(1-2√3)
x=-(6√3-36+3-6√3)/(1-12)
x=-33/11 simplificam cu 3
x=-3
x(1+2√3)=-(6√3+3)
x=-(6√3+3)/(1+2√3) rationalizam
x=-(6√3+3)(1-2√3)/(1+2√3)(1-2√3)
x=-(6√3-36+3-6√3)/(1-12)
x=-33/11 simplificam cu 3
x=-3