Răspuns:
-deduc moli de substante din ecuatia reactiei chimice
1mol............1mol..............1mol........1mol
Ca(OH)2 + CO2----> CaCO3 + H2O
x...................2mol.............y............z
x=y=z=2mol
-deduc masa solutiei date
M,Ca(OH)2= 74g/mol
m= niuxM=2molx74g/mol= 148gCa(OH)2=md
c= mdx100/ms---> ms= 148x100/2,3g=6434,8g
-deduc masele de produsi de reactie
m,CaCO3= niuxM= 2X100g=200g
m,H2O= 2x18g=36g
Explicație: