Daca stim faptul ca functiile sunt de forma f(x)=ax+b =>
a.)f(x)=2x+3=ax+b =>a=2,b=3
b.)f(x)=3x-2=ax+b =>a=3,b=-2
c.)f(x)=x-1=ax+b =>a=1,b=-1
d.)f(x)=-5x+0=ax+b =>a=-5,b=0
e.)f(x)=0•x-2 =>a=0,b=-2
f.)f(x)=3/2x-2/2=3/2x-1=ax+b =>a=3/2,b=-1
