[tex]V=10 l=10^{-2} m^2\\T_1=27^oC=300K\\p_2=2p_1\\p_1V=\nu RT_1=>p_1=\frac{\nu RT_1}{V}=\frac{2*8,31*300}{10^{-2}}\approx50*10^4Pa=5*10^5Pa\\p_2=2p_1=2*5*10^5=10^6Pa=>p_2=10^6Pa\\\rho=\frac{m}{V}=\frac{mp_1}{\nu RT_1}=\frac{\mu p_1}{RT_1}=\frac{0,028*5*10^5}{8,31*300}=5,61 kg/m^3\\ \frac{p_1}{T_1}=\frac{p_2}{T_2}=>T_2=\frac{T_1p_2}{p_1}=\frac{300*10^6}{5*10^5}=600K[/tex]