Răspuns :
a = nr impar
a+a+2+a+4+a+6 = 24
4a+12 = 24
4a = 12
a = 3
a+2 = 5
a+4 = 7
a+6 = 9
fie a, b, c si d numerele cautate
a + b + c + d = 24
a + (a+2) + (a+4) + (a+6) = 24
4a = 24 - 12
4a = 12
a = 12 : 4
a = 3
b = 5
c = 7
d = 9
a = nr impar
a+a+2+a+4+a+6 = 24
4a+12 = 24
4a = 12
a = 3
a+2 = 5
a+4 = 7
a+6 = 9
fie a, b, c si d numerele cautate
a + b + c + d = 24
a + (a+2) + (a+4) + (a+6) = 24
4a = 24 - 12
4a = 12
a = 12 : 4
a = 3
b = 5
c = 7
d = 9