a)
avem N.particule = 15,055x10la23 molecule Cl2
stim ca 1 mol de orice substanta contine 6,022x10la23 molecule, in conditii normale
=>
1 mol Cl2 .... are 2x35,5 g ....coupa 22,4 L ..si contine 6,022x10la23 molecule
x L .................... 15,055x10la23
= 56 L Cl2
b)
1 mol CO2 ... are 44 g ... ocupa 22,4 L
x g ................... 8,96 L
= 17,6 g CO2
