Explicație pas cu pas:
a)
[tex]a = (9 {}^{2} ) {}^{8} = 3 {}^{32} \\ b = (3 {}^{10} ) {}^{3} = 3{}^{30} \\ c = 27 {}^{11} = 3 {}^{33} \\ b \: a \: c[/tex]
b)
[tex]a = 1 + 2 + 3 + 4 + ... + 31 \\ a = \frac{31 \times 32}{2} = 496 \\ b = 3 \times 2 {}^{5} + 2 {}^{5} \\ b = 4 \times 2 {}^{5} = 256 \\ a > b[/tex]
