Răspuns:
[tex]E(-\frac{5}{3})=\frac{3(-\frac{5}{3})+5}{2(-\frac{5}{3})-1} =\frac{-\frac{15}{3}+3)5}{-\frac{10}{3}-3)1} =\frac{\frac{-15+15}{3} }{\frac{-10-3}{3}}=\frac{\frac{0}{3}}{-\frac{13}{3}} =0[/tex] ∈ Z
[tex]E(-\frac{1}{2})=\frac{3(-\frac{1}{2})+5}{2(-\frac{1}{2})-1} =\frac{-\frac{3}{2}+2)5}{-\frac{2}{2}-1} =\frac{\frac{-3+10}{2} }{-2}=\frac{-\frac{7}{2}}{-2} =\frac{7}{4}[/tex]∉Z
[tex]E(\frac{1}{2})=\frac{3(\frac{1}{2})+5}{2(\frac{1}{2})-1} =\frac{\frac{3}{2}+2)5}{\frac{2}{2}-1} =\frac{\frac{3+10}{2} }{0}=\frac{\frac{13}{2}}{0}[/tex]∉Z
[tex]E(\frac{5}{3})=\frac{3(\frac{5}{3})+5}{2(\frac{5}{3})-1} =\frac{\frac{15}{3}+3)5}{\frac{10}{3}-3)1} =\frac{\frac{15+15}{3} }{\frac{10-3}{3}}=\frac{\frac{30}{3}}{\frac{7}{3}} =\frac{20}{7}[/tex]∉Z
A={0}
Explicație pas cu pas:
Inlocuiesti pe x in E(x) cu fiecare din valorile date si afli care dintre ele indeplineste conditia.
