1/.
consideram ca intre anilina si aceton nu avem reactie (desi ele reactioneaza relativ usor)
md = 150 g , V.solvent = 1 L (ro.acetona = 0,785 g/cm3)
ms.solvent = ro x V = 0,785x1000 = 785 g
ms.formata = m.solvent+md = 150+785 = 935 g
c% = mdx100/ms
= 150x100/935 = 16,04%
2/.
Vs.final = V.apa+V.amina = 0,5+0,5 = 1 L
stim ca Cm = nr.moli/Vs
nr.moli = CmxVs = 0,5x0,2 = 0,01 moli
=> Cm.final = nr.moli/Vs.final
= 0,01/1 = 0,01 M