Răspuns :

1+x^2+(1+x)^2=-2x

Ducem -2x in stinga

1+x^2+2x+(1+x)^2=0

(1+x)^2+(1+x)^2=0

2(1+x)^2=0 |÷2

(1+x)^2=0

Deci x=-1 este radacina dubla.