calculei masele molare pt fiecare compus
AgNO3 = 108+14+3*16=170 g/mol
HCl = 35,5+1=36,5 g/mol
AgCl = 108+35,5=143,5 g/mol
HNO3 = 1+14+3*16=63 g/mol
Insumand toate acele mase in ambele parti:reactanti si produsi obtii
170+36,5 ---> 143,5 + 63 => 206,5--->206,5 (A) => se conserva masa substantelor