Răspuns :
Date:
Ec=192J
m=6kg
Rezolvare:
[tex]v= \sqrt{ \frac{2Ec}{m} } [/tex]
[tex]v= \sqrt{ \frac{384}{6} } [/tex][tex]= \sqrt{64} =8m/s[/tex]
Ec=192J
m=6kg
Rezolvare:
[tex]v= \sqrt{ \frac{2Ec}{m} } [/tex]
[tex]v= \sqrt{ \frac{384}{6} } [/tex][tex]= \sqrt{64} =8m/s[/tex]
m=6kg
Ec=192j
v=?
Ec=v²×m
v²=2Ecsupra m
v²=2×192supra m
v²=384supra6kg....dam radical pe disparitia patratului,si avem :
v=√64
v=8m/s
Ec=192j
v=?
Ec=v²×m
v²=2Ecsupra m
v²=2×192supra m
v²=384supra6kg....dam radical pe disparitia patratului,si avem :
v=√64
v=8m/s