Răspuns :
m(A)+m(B)+m(C) d.p cu 3,15 si 18
m(A)/5 + m(B)/15+m(C)/18=k
m(A)=3k
m(B)=15k
m(C)=18k
36k=180
k=180:36
k=5
m(A)=3*5=15
m(B)=15*5=75
m(C)=18*5=80
V.15+75+80=180
m(A)/5 + m(B)/15+m(C)/18=k
m(A)=3k
m(B)=15k
m(C)=18k
36k=180
k=180:36
k=5
m(A)=3*5=15
m(B)=15*5=75
m(C)=18*5=80
V.15+75+80=180