Răspuns :
1) 3p+2c=38
5p-20=c
3p+2(5p-20)=38
3p+10p-40=38
13p=38+40
13p=78
p=6lei
5*6-20=c
30-20=c
c=10lei
5p-20=c
3p+2(5p-20)=38
3p+10p-40=38
13p=38+40
13p=78
p=6lei
5*6-20=c
30-20=c
c=10lei
3p+2c=38
5p=c+20⇒c=5p-20
3p+2(5p-20)=38
3p+10p-40=38
13p=38+40
13p=78
p=78/13=6
A(n)=n(n^3+2n^2-n-2)
n^3+2n^2
c=5·6-20=30-20=10
deci i pix costa 6 lei iar un caiet 10 lei
5p=c+20⇒c=5p-20
3p+2(5p-20)=38
3p+10p-40=38
13p=38+40
13p=78
p=78/13=6
A(n)=n(n^3+2n^2-n-2)
n^3+2n^2
c=5·6-20=30-20=10
deci i pix costa 6 lei iar un caiet 10 lei