Răspuns :

PorumboiuDenisaid
a=k/0,2=k/1/5=5k
b=k/0,5=k/1/2=2k
c=k/0,25=4k
5k+2k+4k=120
11k=120
k=10,90
a=54,5
b=21,8
c=43,6
Crisforpid
x*0,2 = y* 0,5=z*0,25 => x/5 = y/2 = z/4 = k => x = 5k; y = 2k; z = 4k;
x + y + z = 120 => 5k + 2k + 4k = 120 => 11k = 120 => k = 120/11;
atunci x = 600/11; y = 240/11 si z = 480/11;


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