Răspuns :
Facem mezii si extremii => (2x-1)*2<(3x+2)*3 <=>
4x-2<9x+6 <=> (4x-4x)-2<(9x-4x) + 6 ---- am scazut "4x" in intreaga inecuatie
<=> -2>5x+6 <=> -8<5x <=> (-8)/5<x <=> x ∈(-8/5 ; + infinit)
4x-2<9x+6 <=> (4x-4x)-2<(9x-4x) + 6 ---- am scazut "4x" in intreaga inecuatie
<=> -2>5x+6 <=> -8<5x <=> (-8)/5<x <=> x ∈(-8/5 ; + infinit)