Răspuns :

Raheemid
x²+3x+3=0
Δ=b²-4ac
Δ=9-8=1
x1=-b-√Δ/2a =-3-1/2 =-4/2 =-2
x2=-3+1/2=-2/2=-1
a(x-x1)(x-x2)=(x+2)(x+1)
Dupa modelul asta le faci si pe celalalte . BAFTA !
a)(x+1)(x+2)
b)(x+3)(x+2)
c)(x+3)(x+4)
d)(x-2)(x-8)
e)(x-1)(x-6)
f)(x-4)(x-5)
g)(x+2)(x+6)
h)(x-5)(x-10)

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