Răspuns :
(2x + 5)(2x - 3) - (x - 2)(x - 3) - (x - 2)(x + 1)=
=4x²-6x+10x-15-(x²-3x-2x+6)-(x²+x-2x-2)=
=4x²-4x-15-x²+5x-6-x²+x+2=
=2x²+2x-19
=4x²-6x+10x-15-(x²-3x-2x+6)-(x²+x-2x-2)=
=4x²-4x-15-x²+5x-6-x²+x+2=
=2x²+2x-19
(2x+5) (2x-3) - (x-2)(x-3)-(x-2)(x+1)=
=(2x+5)(2x-3)-(x-2)(x-3+x+1)=
=(2x+5)(2x-3)-(x-2)²·2=
=4x²+10x-6x-15-(2x²-8x+8)=
=2x²+12x-23
=(2x+5)(2x-3)-(x-2)(x-3+x+1)=
=(2x+5)(2x-3)-(x-2)²·2=
=4x²+10x-6x-15-(2x²-8x+8)=
=2x²+12x-23