Răspuns :
3√2(6√2+2√6)=
3r2*6r2+3r2*2r6=
18*2( *2 pt ca avem radical din doi ori radical din 2, deci radical din 4=2 )+6r12=
36+6r12=
36+6*2r3=
36+12r3=
12(3+r3)
3r2*6r2+3r2*2r6=
18*2( *2 pt ca avem radical din doi ori radical din 2, deci radical din 4=2 )+6r12=
36+6r12=
36+6*2r3=
36+12r3=
12(3+r3)
3rad2*6rad2=18*2=36
3rad2*2rad6=6rad12=>12=2la 2*3=2rad 3=>6rad12=12rad3
36+12rad3=12(3+rad3)
3rad2*2rad6=6rad12=>12=2la 2*3=2rad 3=>6rad12=12rad3
36+12rad3=12(3+rad3)