Răspuns :

Andrei115id
M de NaOH = A de Na + A de O + A de H = 23+16+1 = 40
Daca 1 mol de NaOH ..........40 g
           x .........................   230 g

x= 230 / 40 = 5, 75 moli

Daca 1 mol ...........40 g NaOH.................23 g Na
         5,75 moli........230 g NaOH...............x

x = (230 *23) / 40
x = 132,25 g Na
Sudoku95id
masa molara NaOH = A sodiu + A hidrogen + A oxigen = 16+1+23=40 g/mol
40 g NaOH........23 g Na
x g NaOH..........230 g Na        x = 400 g NaOH
nr moli = m/μ = 400/40 = 10 moli NaOH

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