Răspuns :
Mase atomice:
H-1
O-16
N-14
M=1*1+14+16*3=48+14+1=63 => 1 mol are 63 g HNO3
63 g HNO3........6,023*10 la puterea 23 atomi (numarul lui Avogadro)
630 g HNO3....... x atomi
x= 6,023* 10 la puterea 23*630/63=6,023*10 la puterea 24 atomi
H-1
O-16
N-14
M=1*1+14+16*3=48+14+1=63 => 1 mol are 63 g HNO3
63 g HNO3........6,023*10 la puterea 23 atomi (numarul lui Avogadro)
630 g HNO3....... x atomi
x= 6,023* 10 la puterea 23*630/63=6,023*10 la puterea 24 atomi
H-1
O-16
N-14
M=1*1+14+16*3=48+14+1=63 => 1 mol are 63 g HNO3
63 g HNO3........6,023*10
630 g HNO3....... x atomi
x= 6,023* 10 la puterea 23*630/63=6,023*10 la puterea 24 atomi
O-16
N-14
M=1*1+14+16*3=48+14+1=63 => 1 mol are 63 g HNO3
63 g HNO3........6,023*10
630 g HNO3....... x atomi
x= 6,023* 10 la puterea 23*630/63=6,023*10 la puterea 24 atomi