5/√6-1 rationalizam cu √6+1 si obtinem
5(√6+1)/(√6-1)(√6+1)= 5(√6+1)=6-1 =5(√6+1)/5=√6+1
3/3+√6 rationalizam cu 3-√6=3(3-√6)/9-6= 3(3-√6)/3=3-√6
7/√11-2 rationalizam cu √11+2 7(√11+2)/11-4 = 7(√11+2)/7= √11+2
14/5+√11 rationalizam cu 5-√11 14(5-√11)/25-11= 14(5-√11)/14=5-√11
√6+1+3-√6+√11+2+5-√11 se simplifica radicalii
1+3+2+5=11
