Răspuns :

AndreDedeid
x(3) - 2x + 1 = x(3) - x - x + 1 = x ( x(2) - 1) - (x - 1) = x (x - 1)(x + 1) - (x - 1) = 
                    = (x - 1) [ x (x + 1) - 1 ] = (x - 1)( x(2) + x - 1)

x(3) si x(2) inseamna x la puterea a 3 a, respectiv la a 2 a
[tex] x^{3}-2x+1= x^{3}-x-x+1=x( x^{2} -1)-(x-1)= [/tex]
[tex]x(x-1)(x+1)-(x-1)=(x-1)[x(x+1)-1]=(x-1)( x^{2} +x-1)[/tex]

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