Răspuns :
a) Ca(OH)₂
Calculam masa molara M= 40 + 2*1 +2*16 =58
Masa molara e echivalenta cu un mol,deci
58 g Ca(OH)₂ ....1 mol
x g Ca(OH)₂.....5 moli
x= (58 * 5 ) /1 =290
b) 6,022 * 10²³ e echivalent cu un mol deci
6,022 * 10 ²³....1 mol
72,264 * 10 ²³...y moli
y= 72,264*10²³ / 6,022 * 10²³=12
c) 255 g NH₃
Masa moleculara (M) = 14* 3*1=17
17 g NH₃....1 mol
255 g NH₃...z moli
z= "55/17=15
d)
6,022*10²³.....1 mol
123,484 * 10²³....a moli
a=123,484 * 10²³/ 6,022*10²³=20,5 moli
e) 10 moli molecule P₄
Sincer,nu stiu cum se rezolva asta.Am cateva idei,dar nu sunt sigura daca sunt corecte.Chiar imi pare rau. :(
Dar sper ca te-am ajutat cu celelalte. :) Bafta
Calculam masa molara M= 40 + 2*1 +2*16 =58
Masa molara e echivalenta cu un mol,deci
58 g Ca(OH)₂ ....1 mol
x g Ca(OH)₂.....5 moli
x= (58 * 5 ) /1 =290
b) 6,022 * 10²³ e echivalent cu un mol deci
6,022 * 10 ²³....1 mol
72,264 * 10 ²³...y moli
y= 72,264*10²³ / 6,022 * 10²³=12
c) 255 g NH₃
Masa moleculara (M) = 14* 3*1=17
17 g NH₃....1 mol
255 g NH₃...z moli
z= "55/17=15
d)
6,022*10²³.....1 mol
123,484 * 10²³....a moli
a=123,484 * 10²³/ 6,022*10²³=20,5 moli
e) 10 moli molecule P₄
Sincer,nu stiu cum se rezolva asta.Am cateva idei,dar nu sunt sigura daca sunt corecte.Chiar imi pare rau. :(
Dar sper ca te-am ajutat cu celelalte. :) Bafta