Stii formula V= nr moli * volum in cond normale(22,4)
nr moli = V/22.4 => nr moli = 3 atat pt amoniac cat si pt azot molecular
a)nr moli N2 = m N2/masa moleculara N2
m N2 = nr moli * masa moleculara = 3 * 28 =>m N2 = 84 g
b)nr moli NH3 = m NH3/masa moleculara NH3
m NH3 = nr moli * masa moleculara = 3 * 17 =>m NH3 = 51 g