Ecuatia reactiei
CaCo3--->CaO+CO2
a) puritatea=(masa pura/masa totala)*100=>masa pura=80*2 tone/100=1,6 tone
1,6 tone CaCO3...........x tone CaO
100g CaCO3................56 g CaO x=0,896 tone=896kg
b)1,6 tone CaCO3...........y tone CO2
100g CaCO3..................44g CO2 y=0,704tone=704kg
nr moli=masa/masa molara=> nr moli CO2=704/44=16 kmoli
c)CaO + H2O --------> Ca(OH)2
56 g CaO..........74g Ca(OH)2
896 kg CaO...........z kg Ca(OH)2 z=1184 kg
c%=(md/ms)*100=>ms=(md/c%)*100=(1184/2)*100=>ms=59200kg=59,2 tone