1.Intr-un triunghi dreptunghic ABC,m(<A)=90celsusi ,AD l BC,D ∈ (BC), se da : a)BC=25 cm si CD =16cm .Calculati BD,AB si AC. b)BC=20cm si BD =16cm.calculat CD,AB si AC. c)AB=15cm si BD =9cm.calculati BC,CD,AC.
a) BD=BC-CD=25-16=9cm; (teorema cateteti) AB²=BD*BC⇒AB²=9*25=225⇒AB=√225=15cm (teorema lui pitagora) BC²=AB²+AC²⇒AC²=BC²-AB²⇒AC²=25²-15²=625-225=400 AC=√400=20cm
