Răspuns :
Teorema inaltimii in ΔABC: AD²=BD·DC=3DC² ⇒ DC=√2 cm; BD=3DC=3√2 cm;
BC=BD+DC=4√2 cm.
BC=BD+DC=4√2 cm.
din T. Inalt ----> AD[tex] AD^{2} = BD*DC ------> 6=3DC*DC
DC= \sqrt{2} -----[/tex]
BD=3[tex] \sqrt{2} [/tex] -------> BD= 4[tex] \sqrt{2} [/tex]
BD=3[tex] \sqrt{2} [/tex] -------> BD= 4[tex] \sqrt{2} [/tex]