(1+i√3)²= 1²+2·1·√3+√3² = 1+2√3+3=4+2√3
(1+i√3)³=(4+2√3)·(1+i√3)=4+4i√3+2√3+6i
(1+i)²= 1+2i-1=2i
(1+i)^4 = 2i·2i= -4
(1+i)^6= (1+i)^4 · (1+i)² = -4 ·2i = -8i
(1+i)^7= (1+i)^6 · (1+i) = -8i (1+i) = -8i + 8
Conjugata este 8+8i
Deci produsul este (4+4i√3+2√3+6i)·(8+8i) = 32+32i√3+16√3+48i+32i-32√3+16√3-48
Te las pe tine sa calculezi :))
