Răspuns :

[tex] a^{2} + b^{2} -2a+6b+10= a^{2} -2a+1+ b^{2} +6b+9= [/tex]
[tex] (a-1)^{2}+ (b+3)^{2}=0 [/tex]
Avem suma a doua patrate perfecte egala cu 0 deci cele doua patrate perfecte vor fi 0,
adica (a-1)² =0, a=1; (b+3)²=0, b=-3

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