Răspuns :
2Mg + 2H2O->2 MgOH+H2
nH2O=10 moli.
mMg=?
nMgOH=?
VH2(c.n)=?
Rezolvare:
a).mMg= n•A;AMg=24moli;nMg=2*10:2=10 moli=> mMg=n•A=240 g.
b).nMgOH=2•10:2=10 moli.
c). VH2=nH2/22,4.
nH2=1•10:2=5 moli. => VH2= 5/22,4
Mg + 2 H2O ---> Mg(OH)2 + H2
1 mol Mg.......2 moli H2O.......1 mol Mg(OH)2........22,4 l H2
x moli Mg......10 moli H2O........y moli Mg(OH)2.........z l H2
x = 5 moli Mg
y = 5 moli Mg(OH)2
z = 112 l H2
1 mol Mg.......2 moli H2O.......1 mol Mg(OH)2........22,4 l H2
x moli Mg......10 moli H2O........y moli Mg(OH)2.........z l H2
x = 5 moli Mg
y = 5 moli Mg(OH)2
z = 112 l H2