AlexandraMariakikiid
a fost răspuns

Va rog rezolvați exercițiul,daca se poate si calcule.Voi scrie / in loc de putere.
5/7:25/13+5/2/0*(625:5/4+5/2:(5+5/2-120/1))
2/30::2/25+2/4/0-2/1(128:2/5+2/3:(2*2/4-24/1))
Aflați ultima cifra a numărului:N=1/33+44/34+7/35

Răspuns :

Imirzincuid
5/7:25/13+5/2/0*(625:5/4+5/2:(5+5/2-120/1))
2/30::2/25+2/4/0-2/1(128:2/5+2/3:(2*2/4-24/1))∛[tex] \left \{ {{y=2} \atop {x=2}} \right. \lim_{n \to \infty} a_n \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] [/tex]

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