a fost răspuns

consideram multimea D₁₈ si multimea  A = { x∈N: x <50 ; x / 12 }

calculati: 

a) A n D₁₈
                                            

b) A u D₁₈


c)A-D₁₈

Răspuns :

D₁₈=multimea divizorilor lui 18, D₁₈={-18, -9,-6,-3,-2,-1,1,2,3,2,9,18}
x I 12  x e natural atunci  A={1,2,3,4,6,12}
a)  A n D₁₈={1,2,3,6}
b) A U D₁₈={{-18, -9,-6,-3,-2,-1,1,2,3,4,6,12,18}
c) A-D₁₈={4,12}
D₁₈={-18, -9,-6,-3,-2,-1,1,2,3,2,9,18}
x I 12  x e natural =>  A={1,2,3,4,6,12}
a)  A n D₁₈={1,2,3,6}
b) A U D₁₈={{-18, -9,-6,-3,-2,-1,1,2,3,4,6,12,18}
c) A-D₁₈={4,12}

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