Răspuns :
1.a. x:7=10 rest 3 => a=10x7+3 => a=70+3 => a=73
b. 3x57-2x57=
=171-114=
=57
c. B=(b+c)-(a+b)
B=7-5
B=2
A=(a+b)-b
A=5-2
A=3
C=(b+c)-b
C=7-2
C=5
2a+5b+3c=2*3+5*3+3*5 = 36
2. a:3+(369-216)=375-31
a:3+153=344
a:3=344-153
a:3=191
a=191x3
a=573
3. a+b=246
a=5b
inlocuim in prima relatie si vom obtine:
5b+b=246 => 6b=246 => b=246:6 => b= 41
a=5x41 => a=205
b. 3x57-2x57=
=171-114=
=57
c. B=(b+c)-(a+b)
B=7-5
B=2
A=(a+b)-b
A=5-2
A=3
C=(b+c)-b
C=7-2
C=5
2a+5b+3c=2*3+5*3+3*5 = 36
2. a:3+(369-216)=375-31
a:3+153=344
a:3=344-153
a:3=191
a=191x3
a=573
3. a+b=246
a=5b
inlocuim in prima relatie si vom obtine:
5b+b=246 => 6b=246 => b=246:6 => b= 41
a=5x41 => a=205