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a fost răspuns

a) ([tex] \frac{2}\sqrt{3} [/tex] + [tex] \frac{3}\sqrt{2} [/tex] ) x 6 - ( [tex] \frac{1}\sqrt{12}[/tex] - [tex] \frac{1}\sqrt{8} [/tex] ) * [tex] \sqrt{24} [/tex] =

Răspuns :

[tex]\frac{2\sqrt2+3\sqrt3}{\sqrt6}*6-\frac{\sqrt2-\sqrt3}{\sqrt{24}}*\sqrt{24}=[/tex]
[tex]=2\sqrt{12}+3\sqrt{18}-\sqrt2+\sqrt3=[/tex]
[tex]=4\sqrt3+9\sqrt2-\sqrt2+\sqrt3=5\sqrt3+8\sqrt2[/tex]
PopAdrianid
[tex]= (\frac{2 \sqrt{3} }{3} + \frac{3 \sqrt{2} }{2})*6 - \frac{ \sqrt{2}- \sqrt{3} }{ \sqrt{24}} * \sqrt{24} \\\\ = \frac{ 4\sqrt{3}+6 \sqrt{2} }{6} * 6 - \sqrt{2} + \sqrt{3} \\\\ = 4\sqrt{3}+6 \sqrt{2} - \sqrt{2} + \sqrt{3}\\\\ = 5 \sqrt{2} + 5 \sqrt{3} [/tex]

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