[tex]( \frac{ \sqrt{2} }{3}+ \frac{ \sqrt{3} }{2}+\frac{ \sqrt{1} }{6}): \sqrt{6}= \frac{2 \sqrt{2}+3 \sqrt{3} +1 }{6} * \frac{1}{ \sqrt{6} } =\frac{2 \sqrt{2}+3 \sqrt{3} +1 }{6}* \frac{ \sqrt{6} }{6} = [/tex]
[tex]=\frac{2 \sqrt{12}+3 \sqrt{18} +1}{36} = \frac{4 \sqrt{3}+9 \sqrt{2} +1 }{36} [/tex]