Răspuns :
[tex](4^2*2^{13})*8^7+(27^4*9^5):3^{20}= \\ \\ =(2^2)^2* 2^{13}*(2^3)^7+(3^3)^4*(3^2)^5:3^{20}= \\ \\ = 2^4*2^{13}*2^{21}+3^{12}*3^{10}:3^{20}= \\ \\ = 2^{38}+3^{22}:3^{20}= \\ \\ =2^{38}+3^2= \\ \\ =\boxed{2^{38}+9}[/tex]
16 ori 304ori 8 la puterea 7 + 27 la puterea 4 ori 95 imparrtit 3 la puterea 20 . de aici e usor de rezolvat .