Răspuns :

(a+a+1+a+2):7=24 rest 6
(a+a+1+a+2)=24*7+6

3a+3+174
3a=174-3
3a=171
a=57

a+1=57+1=58
a+2=57+2=59

Numerele sunt : 57 , 58 , 59 
Absolvantid
x= a+b+c
x:7=24 r 6
x= 7x24 +6 = 168 + 6 = 174.
a,b,c = nr consecutive => c= a+2, b=a+1=>
=> a + a + 1 + a + 2 = 174
3a +3 =174/-3
3a = 171 /:3
a= 57
b=58
c=59 

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