Răspuns :

a=k/4
b=k/5
c=k/6
d=k/10
2(a+b)-5c+d=10
2(k/4+k/5)-5·k/6+k/10=10
18k/20+k/10-5k/6=10
9k/10+k/10-5k/6=10
k-5k/6=10
(6k-5k)/6=10
k/6=10
k=60
a=60/4=15
b=60/5=12
c=60/6=10
d=60/10=6
Presupun ca aceasta este rezolvarea pe care o doresti.
Prof De Mate