Răspuns :
(a+a+1+a+2):7=24 rest 6
(a+a+1+a+2)=24*7+6
3a+3=174
3a=171
a=57
a+1=57+1=58
a+2=57+2=59
Deci numerele sunt : 57 , 58 , 59 .
(a+a+1+a+2)=24*7+6
3a+3=174
3a=171
a=57
a+1=57+1=58
a+2=57+2=59
Deci numerele sunt : 57 , 58 , 59 .