Răspuns :
[tex] \sqrt{ 9^{x} 4^{y} } =72<=> 9^{x} 4^{y} =5184<=>x=2,y=3[/tex]
72 = 2³ * 3²
[tex] Mg=\sqrt{ 9^{x} * 4^{y}}=\sqrt{ 3^{2x}*2^{2y}}=\sqrt{3^{2x}}*\sqrt{2^{2y}}= 3^{x}* 2^{y} \\ 3^{x}* 2^{y}=72 \\3^{x}* 2^{y}= 2^{3}*3^{2} \\ => \\ x=2 \\ y=3 [/tex]
[tex] Mg=\sqrt{ 9^{x} * 4^{y}}=\sqrt{ 3^{2x}*2^{2y}}=\sqrt{3^{2x}}*\sqrt{2^{2y}}= 3^{x}* 2^{y} \\ 3^{x}* 2^{y}=72 \\3^{x}* 2^{y}= 2^{3}*3^{2} \\ => \\ x=2 \\ y=3 [/tex]