Răspuns :
x-lungimea drumului
7/20 din x= 7/20 *x = 7x/20 - prima data
x-7x/20= (20x-7x)/20= 13x/20 -restul
1/5 din 13x/20= 1/5 * 13x/20= 13x/100 -a doua oara
13x/20 -13x/100= (65x-13x)/100= 52x/100 -noul rest
52x/100=624
x=100*624/52
x=100*12
x=1200
13*1200/100= 13*12= 156 a parcurs a doua oara
7/20 din x= 7/20 *x = 7x/20 - prima data
x-7x/20= (20x-7x)/20= 13x/20 -restul
1/5 din 13x/20= 1/5 * 13x/20= 13x/100 -a doua oara
13x/20 -13x/100= (65x-13x)/100= 52x/100 -noul rest
52x/100=624
x=100*624/52
x=100*12
x=1200
13*1200/100= 13*12= 156 a parcurs a doua oara
Notezi toata distanta drumulului cu x
deci x= I +II+ III
prima zi I=7/20 *x
a doua zi II=1/5(x-I)= 1/5(x-7/20*x)
a treia zi III=624 km
=> x= 7/20*x +1/5 (x-7/20 *x) +624
aducem la acelasi numitor si avem (numitor comn 100)
100x=35x+20x-7x+62400
100x=55x-7x+62400
100x=48x+62400
100x-48x=62400
52x=62400
x=62400/52
x=1200 km
I= 7/20 *1200=420 km in prima zi
II=1200-420-624=156 km in a doua zi
deci x= I +II+ III
prima zi I=7/20 *x
a doua zi II=1/5(x-I)= 1/5(x-7/20*x)
a treia zi III=624 km
=> x= 7/20*x +1/5 (x-7/20 *x) +624
aducem la acelasi numitor si avem (numitor comn 100)
100x=35x+20x-7x+62400
100x=55x-7x+62400
100x=48x+62400
100x-48x=62400
52x=62400
x=62400/52
x=1200 km
I= 7/20 *1200=420 km in prima zi
II=1200-420-624=156 km in a doua zi