Răspuns :

Miky93id
ΔABC, mas<A=90
AB=AC=x

A=c1 * c2/2=  18

x*x =18*2

x²=36   => x= 6

AB=AC=6

BC²=AB²+AC²=6²+6²=  36+36 =72   => BC=6√2

P ΔABC=AB+AC+BC= 6+6+6√2=  12+6√2

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