Suma a doua numere este 25,iar diferenta lor13.Care sunt cele doua numere?
3(×+5)-5(1-×)(1+×)=(×+3)la a doua+(2×-1)la a doua+13

1. x+y=25
x-y=13
x=13+y
13+y+y=25
13+2y=25
2y=12
y=6
x=13+6=19

2. 3x+5 - 5(1-x²) = x²+6x+9+4x²-4x+1+13
3x+15-5+5x²=x²+6x+9+4x²-4x+1+13
3x+10+5x²=x²+6x+4x²-4x+23
3x+5x²-x²-6x-4x²+4x=23-10
x=13

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Miky93id Miky93id · Answer 2

Miky93id Miky93id

1)a+b=25
a-b=13 adunam cele 2 ecuatii
2a / = 38

a=19 =>b=25-19=6

2)3x +15 -5(1-x²) = x² +6x +9 +4x² -4x+1 +13

3x +15 -5 +5x² = 5x² +2x +14

3x +15 +5x² -5 =5x² +2x +14

3x +10 =2x +14

3x-2x= 14-10

x=4

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Suma a doua numere este 25,iar diferenta lor13.Care sunt cele doua numere?3(×+5)-5(1-×)(1+×)=(×+3)la a doua+(2×-1)la a doua+13

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Suma a doua numere este 25,iar diferenta lor13.Care sunt cele doua numere?
3(×+5)-5(1-×)(1+×)=(×+3)la a doua+(2×-1)la a doua+13