Răspuns :

1,7(3)= 1intreg  (73-7)/90=  1 intreg 66/90 = 1 intreg 22/30= 52/30= 26/15

a= 1/3 din b=  1/3 * b=  b/3

b= 1/3 din c= 1/3 * c= c/3

a=c/3/3= c/3 * 1/3= c/9

ma=(a+b+c)/3= 26/15

a+b+c= 3*26/15

a+b=c= 26/5

c/9 + c/3 + c= 26/5  aducem la acelasi numitor

5c + 15c +45c= 234

65c= 234

c=3,6

a= 3,6/9= 0,4

b= 3,6/3= 1,2