Efectuati calculele:
a) [tex] \frac{1}{ \sqrt{2}+1 }+ \frac{1}{ \sqrt{3}+ \sqrt{2} } + \frac{1}{ \sqrt{5}+ \sqrt{4} } + \frac{1}{ \sqrt{4}+ \sqrt{3} }=[/tex]

b) [tex] \frac{9}{ \sqrt{18} }- \frac{9}{ \sqrt{8}} + \frac{9}{6 \sqrt{2} } - \frac{9}{6 \sqrt{8} }= [/tex]

1)(√2-1)/(2-1) + (√3-√2)/(3-2) + (√5-√4)/(5-4) + (√4-√3)/(4-3)=

√2 -1 + √3 -√2 +√5 -2 +2 -√3=

= -1 +√5

2)9√18/18 -9√8/8 +9√2/12 -9√8/6*8=

=3√2/2 -9√2/4 + 3√2/4 -3√2/8 aducem la acelasi numitor

= (12√2 - 18√2 + 6√2 -3√2)/8=

=(18√2 -21√2)/8= -3√2/8

Answer Link

Efectuati calculele:a) [tex] \frac{1}{ \sqrt{2}+1 }+ \frac{1}{ \sqrt{3}+ \sqrt{2} } + \frac{1}{ \sqrt{5}+ \sqrt{4} } + \frac{1}{ \sqrt{4}+ \sqrt{3} }=[/tex]b) [tex] \frac{9}{ \sqrt{18} }- \frac{9}{ \sqrt{8}} + \frac{9}{6 \sqrt{2} } - \frac{9}{6 \sqrt{8} }= [/tex]

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Efectuati calculele:
a) [tex] \frac{1}{ \sqrt{2}+1 }+ \frac{1}{ \sqrt{3}+ \sqrt{2} } + \frac{1}{ \sqrt{5}+ \sqrt{4} } + \frac{1}{ \sqrt{4}+ \sqrt{3} }=[/tex]

b) [tex] \frac{9}{ \sqrt{18} }- \frac{9}{ \sqrt{8}} + \frac{9}{6 \sqrt{2} } - \frac{9}{6 \sqrt{8} }= [/tex]